Answer:
The dimensions of the room would be 10 x 6
Step-by-step explanation:
In order to find this, start with the perimeter formula and solve for either variable.
P = 2L + 2W
32 = 2L + 2W
2L = 32 - 2W
L = 16 - W
Now we input that into the L part of the area equation.
A = LW
60 = LW
60 = (16 - W)W
60 = 16W - W^2
W^2 + 60 = 16W
W^2 - 16W + 60 = 0
Now we can factor this.
(W - 10)(W - 6)
And to solve we set each parenthesis equal to 0
W - 10 = 0
W = 10
W - 6 = 0
W = 6
So we know these are the two possible dimensions.
