Answer:
Remainder is 691.
Step-by-step explanation:
Given function is [tex]10x^4-6x^3+5x^2-x+1[/tex].
Now we need to find remainder if we divide given function [tex]10x^4-6x^3+5x^2-x+1[/tex] by (x-3)
(x-3) means plug x=3 into [tex]10x^4-6x^3+5x^2-x+1[/tex] to find remainder.
[tex]10x^4-6x^3+5x^2-x+1[/tex]
[tex]=10(3)^4-6(3)^3+5(3)^2-(3)+1[/tex]
[tex]=10(81)-6(27)+5(9)-(3)+1[/tex]
[tex]=810-162+45-3+1[/tex]
[tex]=856-162-3[/tex]
[tex]=856-165[/tex]
[tex]=691[/tex]
Hence remainder is 691.
Answer:
The remainder = 691
Step-by-step explanation:
Let p(x) = 10x⁴ - 6x³ + 5x² - x + 1
We have to divide p(x) by (x - 3)
To find the remainder we have to find p(3)
To find the remainder
p(x) = 10x⁴ - 6x³ + 5x² - x + 1
p(3) = 10 * (3)⁴ - 6*(3)³ + 5* (3)² - 3 + 1
= (10 * 81 ) - ( 6 * 27 ) + (5 * 9) - 3 + 1
= 810 - 162 + 45 - 3 + 1 = 691
Therefore the remainder is 691