Question

In a basketball game, Marlene made 16 field goals. Each field goals was worth either 2 points or 3 points, and Marlene scored a total of 39 points from field goals. Let x represents the number of two-point field goals and y to model the situation. How many three-point field goals did Marlene make in the game?

Answer 1

Answer:

The number of three-point field goals was $7$

Step-by-step explanation:

Let

x-----> the number of two-point field goals

y-----> the number of three-point field goals

we know that

$x+y=16$

$x=16-y$ -----> equation A

$2x+3y=39$ ----> equation B

substitute equation A in equation B and solve for y

$2(16-y)+3y=39$

$32-2y+3y=39$

$y=39-32=7$

Answer 2

Using a system of equations, it is found that Marlene made 7 three-point field goals in the game.

What is a system of equations?

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are:

• Variable x: Number of two-point field goals made.

• Variable y: Number of three-point field goals made.

Marlene made 16 field goals, hence:

x + y = 16 -> x = 16 - y

She scored a total of 39 points from field goals, hence:

2x + 3y = 39

2(16 - y) + 3y = 39

32 - 2y + 3y = 39

y = 7

Marlene made 7 three-point field goals in the game.

More can be learned about a system of equations at https://brainly.com/question/24342899