Respuesta :

gmany

Answer:

[tex]\large\boxed{(x+3)^2+(y-2)^2=225}[/tex]

Step-by-step explanation:

The equation of a circle:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

(h, k) - center

r - radius

We have r = 15 and the center (-3, 2). Substitute:

[tex](x-(-3))^2+(y-2)^2=15^2\\\\(x+3)^2+(y-2)^2=225[/tex]

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