Question

Find a number less than 100 that is increased by one-fifth of its value when its digits are reversed.

Answer 1

Lets say the number is ab. Its value is 10a + b  

When it is reversed it is 10b + a = 12a+1.2b (from the condition its value should increase 0.2 times).  

11 a = 8.8b  

a/b = 8.8/11 = 0.8/1 = 8/10 = 4/5 ( we do this because a and b should be natural numbers less than 10).  

answer is 45.

Answer 2

The required number as described is; 45.

Word Problems

From the question;

• The number is less than 100.

Hence, let the number be; xy.

From the task content;

• 10y + x = 12x + 1.2y

Hence, it follows that;

• 8.8y = 11x

• x/y = 8.8/11 = 4/5

Ultimately, the required number is; 45

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