Answer:
B
Step-by-step explanation:
([tex]\frac{f}{g}[/tex])(x)
= [tex]\frac{3x+5}{3x^2-x-10}[/tex] ← factor denominator
= [tex]\frac{3x+5}{(x-2)(3x+5)}[/tex] ← cancel (3x + 5), leaving
= [tex]\frac{1}{x-2}[/tex]
The denominator cannot be zero as this would make the fraction undefined. Equating the denominator to zero and solving gives the value that x cannot be.
solve x - 2 = 0 ⇒ x = 2 ← excluded value
domain is the set of all real numbers except 2
