Question

a teacher is holding tryouts for a school play. there are 15 students trying out for 7 parts in the play each student can play each part. in how many ways can the teacher select the students?

Answer 1

Answer:

6,435

Step-by-step explanation:

To find the number of ways the teacher can select the students, we can use the combination formula.

$_{n}C_{k}=\dfrac{n!}{k!(n-k)!}$

n = 15

k = 7

Now let's plug it in.

$_{n}C_{k}=\dfrac{n!}{k!(n-k)!}$

$_{15}C_{7}=\dfrac{15!}{7!(15-7)!}$

$_{15}C_{7}=\dfrac{15!}{7!8!}$

$_{15}C_{7}=6,435$

So there are 6,435 ways that the teacher can select the students.