Answer: [tex]\bold{\dfrac{-5\pm 2\sqrt{10}}{3}}[/tex]
Step-by-step explanation:
[tex]5-10x-3x^2=0\quad \rightarrow \quad a=-3,\ b=-10,\ c=5\\\\\\\text{Quadratic formula is: }x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(-10)\pm \sqrt{(-10)^2-4(-3)(5)}}{2(-3)}\\\\\\.\ =\dfrac{10\pm \sqrt{100+60}}{2(-3)}\\\\\\.\ =\dfrac{10\pm \sqrt{160}}{2(-3)}\\\\\\.\ =\dfrac{10\pm 4\sqrt{10}}{2(-3)}\\\\\\.\ =\dfrac{-5\pm 2\sqrt{10}}{3}[/tex]
