Question

Write the quadratic equation in general quadratic form below.

17x2 = 12x

Answer 1

Answer:   $\bold{\dfrac{12\pm \sqrt{144-0}}{2(17)}}$

Step-by-step explanation:

$17x^2=12x\quad \rightarrow \quad 17x^2-12x+0=0\quad \rightarrow \quad a=17,\ b=-12,\ c=0\\\\\\\text{Quadratic formula is: }x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(-12)\pm \sqrt{(-12)^2-4(17)(0)}}{2(17)}\\\\\\.\ =\dfrac{12\pm \sqrt{144-0}}{2(17)}$

Answer 2

Answer:

General quadratic form is 17x²- 12x + 0 = 0.

Step-by-step explanation:

Given  : 17x² = 12x.

To find : Write the quadratic equation in general quadratic form below.

Solution : We have given that 17x² = 12x.

General quadratic form is  : $ax^{2} + bx + c = 0$.

We have 17x² = 12x.

Convert it in to general quadratic form

On subtracting both sides by 12x .

17x²- 12x + 0 = 0.

Here a = 17 , b = - 12 , c = 0 .

Therefore, General quadratic form is 17x²- 12x + 0 = 0.