Question

T=−2a^2+a+6
N=−3a^2+2a−5 ​
N − T =

Answer is: −a^2+a−11

Answer 1

Answer:

$\large\boxed{N-T=-a^2+a-11}$

Step-by-step explanation:

$T=-2a^2+a+6\\N=-3a^2+2a-5\\\\N-T=?\\\\\text{Substitute:}\\\\N-T=(-3a^2+2a-5)-(-2a^2+a+6)\\\\N-T=-3a^2+2a-5-(-2a^2)-a-6\\\\N-T=-3a^2+2a-5+2a^2-a-6\qquad\text{combine like terms}\\\\N-T=(-3a^2+2a^2)+(2a-a)+(-5-6)\\\\N-T=-a^2+a-11$

Answer 2

The difference between the functions is $-a^2+a-11$

Given the following expression:

$T=-2a^2+a+6\\N=-3a^2+2a-5$

We are to take the difference between N and T and this is as shown:

$N - T= -3a^2+2a-5-(-2a^2+a+6)\\Expand\\N - T= -3a^2+2a-5+2a^2-a-6\\\\Collect \ the \ like \ terms\\N-T=-3a^2+2a^2+2a-a-5-6\\N-T=-a^2+a-11$

Hence the difference between the functions is $-a^2+a-11$

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