pythagoras
a^2 = b^2 + c^2
a^2 = (8)^2 + (4)^2
a^2 = 64 + 16
a^2 = 80
[tex]a = \sqrt{80} [/tex]
Answer:
The length of the diagonal (d) = 4[tex]\sqrt{5}[/tex] units.
Step-by-step explanation:
We are given the length (l) = 8, width (w) = 4 and height (h) = 2.
Now we have to find the diagonal of the base.
The given figure is a rectangle box. The base of the rectangular box is a rectangle with the length (l) = 8 and the width(w) = 4
The length of the diagonal (d) = [tex]\sqrt{l^2 + w^2}[/tex]
d = [tex]\sqrt{8^2 + 4^2}[/tex]
d = [tex]\sqrt{64 + 16}[/tex]
d = [tex]\sqrt{80}[/tex]
d = [tex]\sqrt{16} \sqrt{5}[/tex]
d = 4[tex]\sqrt{5}[/tex]
So, the length of the diagonal (d) = 4[tex]\sqrt{5}[/tex] units.
