Question

Select the correct answer

Answer 1

Answer:

16

2

Step-by-step explanation:

Given in the question an equation

$\frac{x^2 - 10x + 14}{ x-8}$

The constant term that the numerator must have = 16

To get this number add 2 in the numerator

after which the equation will become

$\frac{x^2 - 10x + 14+2}{ x-8}$

$\frac{x^2 - 10x + 16}{ x-8}$

Now by using factorisation of quadratic equation we have

$\frac{(x-8)(x-2)}{x-8}$

(x-2)

but if we add and subtract 2 in the numerator then

$\frac{x^2 - 10x + 16 -2}{ x-8}$

$\frac{(x-8)(x-2)-2}{x-8}$

$(x-2)-\frac{2}{x-8}$