Answer:Volume occupied by the gas at standard pressure is 162.5 L.
Explanation:
Pressure of the gas when it occupies volume of 190 L = 650 mmHg
Volume occupied by the gas when the gas is at standard pressure.
The value of standard pressure = 1 atm = 760 mmHg
[tex]P_1=650 mmHg,V_1=190 L,P_2=760 mmHg,V_2=?[/tex]
According to Boyle's Law: [tex]Pressure\propto \frac{1}{Volume}[/tex] (at constant temperature)
[tex]P_1\times V_1=P_2\times V_2[/tex]
[tex]V_2=\frac{P_1\times V_1}{P_2}=\frac{650 mmHg\times 190 L}{760 mmHg}=162.5 L[/tex]
Volume occupied by the gas at standard pressure is 162.5 L.