What is the area of the irregular polygon shown below?

Answer:
Step-by-step explanation:
Area of given figure is combination of area of rectangle and area of Pentagon
Area of rectangle = length x width
= 6 x10
= 60 sq units
Area of pentagon =[tex]\frac{a p}{2}[/tex] where a = apothem and p = perimeter
Area of pentagon = [tex]\frac{(4.1)X6(5)}{2}[/tex]
=61.5 sq units
Area of the given figure = area of rectangle + area of pentagon
= 60 + 61.5
121.5 sq units