A point with an abscissa of 3 belongs to the line which is the graph of the equation 21x–5y=100. Find the ordinate of that point.

Respuesta :

The ordinate will be -7.4.

Answer:

  -7.4

Step-by-step explanation:

Put the abscissa value into the equation and solve for the ordinate.

  21·3 -5y = 100

  -5y = 37 . . . . . subtract 63

  y = -7.4 . . . . . . divide by -5

Otras preguntas