the balanced equation for the reaction is
2NaOH + H₂SO₄ ---> Na₂SO₄ + 2H₂O
molar ratio of NaOH to H₂SO₄ is 2:1
limiting reactant is the reagent that is fully consumed in the reaction and determines the amount of product formed and excess reactant is the reactant where only a fraction is used up and theres excess remaining after the reaction
number of NaOH moles added - 5.0 mol
assuming NaOH is the limiting reactant
according to molar ratio, 2 mol of NaOH reacts with 1 mol of H₂SO₄
then 5 mol of NaOH reacts with - 1/2 x 5 = 2.5 mol of H₂SO₄
the number of H₂SO₄ moles added are 5.0 mol
but only 2.5 mol of H₂SO₄ moles is used up therefore H₂SO₄ is the excess reactant and NaOH is limiting reactant and it is fully used up .
answer is 3. NaOH