Respuesta :
Answer:
c. Jupiter's radius is 10 times the Earth's radius
Explanation:
The weight of a person on the surface of a planet is equal to the gravitational pull exerted by the planet on the person:
[tex]F=G\frac{mM}{R^2}[/tex]
where
[tex]G=6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2}[/tex] is the gravitational constant
M is the mass of the planet
m is the mass of the person
R is the radius of the planet
The weight of a person on Earth is given by:
[tex]F_E=G\frac{mM_E}{R_E^2}[/tex]
where [tex]M_E[/tex] is the mass of the Earth and [tex]R_E[/tex] is the Earth's radius.
We know that Jupiter's mass is 300 times the Earth's mass:
[tex]M_J = 300 M_E[/tex]
while Jupiter's radius is 10 times the Earth's radius:
[tex]R_J = 10 R_E[/tex]
So, the weight of the person on Jupiter is
[tex]F_J=G\frac{mM_J}{R_J^2}=G\frac{m(300 M_E)}{(10 R_E)^2}=G \frac{300 mM_E}{100 R_E^2}=3 G\frac{mM_E}{R_E^2}=3 F_E[/tex]
So, the weight would be only 3 times as much.
Answer:
c- Jupiter's radius 10 times the Earth's radius
Explanation: