What are the coordinates of the vertex of the function below? Write your answer in the form (x,y).
![What are the coordinates of the vertex of the function below Write your answer in the form xy class=](https://us-static.z-dn.net/files/dfb/c54f661d46770bea92a64adc5c437075.png)
ANSWER
The vertex is
[tex](5,11)[/tex]
EXPLANATION
The given function is
[tex]y - 11 = - {(x - 5)}^{2} [/tex]
Rewrite in the form;
[tex]y = - {(x - 5)}^{2} + 11[/tex]
This function is in the form;
[tex]y = a {(x - h)}^{2} + k[/tex]
where
[tex](h,k)=(5,11) [/tex]
is the vertex
Answer:
vertex is (5,11).
Step-by-step explanation:
We have given a equation.
y-11 = -(x-5)²
We have to find the vertex of the function.
y = a(x-h)²+k is vertex form of quadratic equation where (h,k) is vertex of equation.
Adding 11 to both sides of given equation, we have
y-11+11 = -(x-5)²+11
y = -(x-5)²+11
Comparing to the vertex form, we have
h = 5 and k = 11
Hence, vertex is (5,11).