Respuesta :

Answer:

see explanation

Step-by-step explanation:

Equate the quadratic to zero

x² - 5x + 4 = 0 ← in standard form

with a = 1, b = - 5, c = 4

Using the quadratic formula to solve for x

x = ( -(- 5) ± [tex]\sqrt{(-5)^2-(4(1)(4)}[/tex] ) / 2

  = ( 5 ± [tex]\sqrt{9}[/tex] ) / 2

  = ( 5 ± 3 ) / 2

  x = [tex]\frac{5-3}{2}[/tex] or x = [tex]\frac{5+3}{2}[/tex], hence

x = 1 or x = 4

The solutions are real, rational and distinct