Answer:
The surface area is [tex]408\ cm^{2}[/tex]
Step-by-step explanation:
we know that
The surface area of the triangular prism is equal to
[tex]SA=2B+PH[/tex]
where
B is the area of the triangular base
P is the perimeter of triangular base
H is the height of the triangular prism
Find the area of the base B
[tex]B=\frac{1}{2}(8)(6)=24\ cm^{2}[/tex]
Find the perimeter of the base P
[tex]P=(8+6+10)=24\ cm[/tex]
we have
[tex]H=15\ cm[/tex]
substitute and find the surface area
[tex]SA=2(24)+(24)(15)=408\ cm^{2}[/tex]
