Respuesta :

Answer : The correct option is, [tex]10^{-4}M[/tex]

Explanation : Given,

pH = 10

First we have to calculate the pOH.

[tex]pH+pOH=14\\\\pOH=14-pH\\\\pOH=14-10=4[/tex]

Now we have to calculate the [tex]OH^-[/tex] concentration.

[tex]pOH=-\log [OH^-][/tex]

[tex]4=-\log [OH^-][/tex]

[tex][OH^-]=1.0\times 10^{-4}M[/tex]

Therefore, the [tex]OH^-[/tex] concentration is, [tex]1.0\times 10^{-4}M[/tex]

ACCESS MORE