Let f(x)=100/-10+e^-0.1x
What is f(−11)?
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For f(-11) replace x with -11 and solve:
f(-11) = 100 / -10 +e^-0.1(-11)
f(-11) = 100 / -10 +e^1.1
f(-11) = -14.3
The value of f(-11) is -14.28.
Given
The given function is;
[tex]\rm f(x)=\dfrac{100}{-10+e^{-0.1x}}\\\\[/tex]
Every element in X is related to Y No element in X has two or more relationships.
The value of f(-11) is found by the substitute the value of x is -11 in the equation.
Then,
The value of f(-11) is;
[tex]\rm f(x)=\dfrac{100}{-10+e^{-0.1x}}\\\\ x=-11\\\\\rm f(-11)=\dfrac{100}{-10+e^{-0.1(-11)}}\\\\ \rm f(x)=\dfrac{100}{-10+e^{1.1}}\\\\ f(-11)=\dfrac{100}{-10+3}}\\\\ f(-11)=\dfrac{100}{-7}}\\\\f(-11)=-14.28[/tex]
Hence, The value of f(-11) is -14.28.
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