Question

Using the transformation T: (x, y) (x + 2, y + 1), find the distance named. Find the distance AB

Answer 1

Answer: $d_{AB}=\sqrt{10}$

Step-by-step explanation:

You must apply the formula for calculate the distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

As you can see in the graph, the coordinates of the point A and the point B are:

A(0,0)

B(1,3)

Substitute values into the formula shown above. Therefore, you obtain that the distance AB is:

$d_{AB}=\sqrt{(1-0)^2+(3-0)^2}$

$d_{AB}=\sqrt{10}$

Answer 2

Answer:

d = √10 units

Step-by-step explanation:

We have given a graph.

We have to find the distance of AB.

As given in graph, The coordinates of A and B are

(0,0) and (1,3) respectively.

The formula to find distance between two points is :

d = √(x₂-x₁)²+(y₂-y₁)²

Putting given values in above formula,we have

d = √(3-0)²+(1-0)²

d =  √(3)²+(1)²

d =  √9+1

d = √10 units which is the answer.