6.5 g Fe2O3 x 1 mol Fe2O3/ 159.9 g Fe2O3 x 2 mol Fe/1 mol Fe2O3 x 55.8 g Fe/ 1 mol Fe = 4.5 g Fe <<< Answer
Steps:
1) start with reactant provided in the question.
2) calculate the grams per mole of that reactant.
3) determine the ratio of the given reactant to the (desired) reactant in the question.
4) calculate the grams per mole of the desired reactant.
If everything cancels out, you've set your factors up properly
Answer:
[tex]m_{CO}=82.13gCO[/tex]
Explanation:
Hello,
Considering the reaction:
[tex]2C+O_2\rightarrow 2CO[/tex]
By means of stoichiometry, the produced grams of CO result:
[tex]m_{CO}=35.2gC*\frac{1molC}{12gC}*\frac{2molCO}{2molC}*\frac{28gCO}{1molCO} \\m_{CO}=82.13gCO[/tex]
Best regards.
