Answer:
Not picking a square.
Not picking a circle.
Step-by-step explanation:
According to the image, there are 2 squares, 4 triangles and 2 circles. Let's find the probability of each figure:
[tex]P_{square}=\frac{2}{8}=\frac{1}{4} \\P_{triangle}=\frac{4}{8}=\frac{1}{2} \\P_{circles}=\frac{2}{8}=\frac{1}{4}[/tex]
However, neither of this have a probability of 3/4.
That means the opposite events are probably the ones.
[tex]P_{not \ square}=\frac{6}{8}=\frac{3}{4} \\P_{not \ triangle}=\frac{4}{8}=\frac{1}{2} \\P_{not \ circles}=\frac{6}{8}=\frac{3}{4}[/tex]
Therefore, not picking a square and not picking a circle have probability of 3/4 exactly.