Respuesta :
The temperature of the gas doubles while the density will remain the same. therefore the correct answer is C.
The gas equation is given as
PV=mRT \\
or\ P\propto T\ \ (\text{at}\ \text{constant}\ \text{volume)}
Therefore when the temperature of the mono atomic ideal gas is doubled, the pressure of the gas will also doubles.
However, in a closed chamber mass of the ideal gas is invariant, since density depends only on the mass and volume therefore the density of the ideal is gas will remain the same.
The temperature of the gas doubles the density will decrease but doubles the pressure.
Effect of temperature on density and pressure
When temperatures increase, objects expand and become larger and therefore the density decreases. When temperatures decrease, objects condense and become smaller so density increases.
The temperature of the gas is directly proportional to its pressure which means temperature increase the pressure.
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