Question

What is your he equation, in point-slope form, of the line that is parallel to the given line and passes through the point the point ( -3, 1)?

Answer 1

Answer:

$\large\boxed{y-1=\dfrac{3}{2}(x+3)}$

Step-by-step explanation:

Calculate the slope of given line:

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points from the graph: (-2, -4) and (2, 2).

Subtitute:

$m=\dfrac{2-(-4)}{2-(-2)}=\dfrac{2+4}{2+2}=\dfrac{6}{4}=\dfrac{3}{2}$

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

We have the point (-3, 1). Parallel lines have the same slope. Therefore the slope m = 3/2. Substitute:

$y-1=\dfrac{3}{2}(x-(-3))$y-1=\dfrac{3}{2}(x+3)