Question

A museum requires a minimum number of chaperones proportional to the number of students on a field trip. The museum requires a minimum of 3 chaperones for a field trip with 24 students. Which of the following could be combinations of values for the students and the minimum number of chaperones the museum requires? Choose 2 answers:

A. Students: 72
Minimum of chaperones: 9

B. Students: 16
Minimum of chaperones: 2

C. Students: 60
Minimum of chaperones: 6

D. Students: 45
Minimum of chaperones: 5

E. Students: 40
Minimum of chaperones: 8

Answer 1

24 students divided by 3 chaperones equals 1 chaperone for every 8 students.

A. 72 / 9 = 8 students per chaperone.  This is correct.

B. 16 / 2 = 8 students per chaperone. This is correct.

C. 60 / 6 = 10 students per chaperone. This is not correct.

D. 45 / 5 = 9 students per chaperone. This is not correct.

E. 40 / 8 = 5 students per chaperone. This is not correct.

The 2 correct answers are A and B.

Answer 2

The combination of values for the students and at least no of chaperones the museum needed is option A and option B.

Given that

There is a minimum no of chaperones required i.e. 3.

And, there are 24 students.

So,  if we divided the 24 by 3 so we can get the 8 students for one chaperone.

Now as per the given options:

A.

$= \frac{72}{9}$

= 8 students per chaperone.

B.

$= \frac{16}{2}$

=  8 students per chaperone.

C.

$= \frac{60}{6}$

= 10 students per chaperone.

D.

$= \frac{45}{5}$

= 9 students per chaperone.

E.

$= \frac{40}{8}$

= 5  students per chaperone.

Therefore we can conclude that the combination of values for the students and at least no of chaperones the museum needed is option A and option B.

Learn more about the proportions here: brainly.com/question/21126582