Answer:
The angle between them = 52.1°
Step-by-step explanation:
∵ The position vector of the first point is [tex]\left[\begin{array}{ccc}1\\5\end{array}\right][/tex]
∵ The position vector of the second point is [tex]\left[\begin{array}{ccc}6\\3\\\end{array}\right][/tex]
∵ The magnitude of the first = √(1²+5²) = √26
∵ The magnitude of the second = √(6²+3²) = √45
∵ The scalar product of them = (1 × 6) + (5 × 3) = 6 + 15 = 21
∵ cosФ = scalar product/(magnitude 1st × magnitude 2nd)
∴ cosФ = 21/(√26 × √45) = 0.61394
∴ Ф = 52.1°
