Question

Calculate the energy of the red light emitted by a neon atom with a wavelength of 703.2 nm.

Answer 1

Answer;

2.826 × 10^-19 Joules

Explanation;

Energy of a wave is given by the formula;

E = hf; where E is the energy, h is the Plank's constant, 6.626 × 10^-34 m²/kg/s and f is the frequency.

But; f = c/λ , where c is the speed of light, 2.998 × 10^8 m/s, and λ is the wavelength 7032 nm.

Therefore;

E = hf = hc/λ

          = (6.626 × 10^-34 × 2.998 × 10^8 m/s)/(7.032 × 10^-6 m)

          = 2.825 × 10^-19 Joules

Answer 2

Answer:

Energy = 2.83*10^-19 J

Explanation:

Given:

Wavelength (λ) emitted by a Neon atom = 703.2 nm

To determine:

Energy (E) of the photon of light

Explanation:

Energy (E) pf a photon is related to its wavelength (λ) by the Planck's equation:

$E = \frac{hc}{\lambda}$

where h = Planck's constant = 6.626*10^-34 Js

c = speed of light = 3*10^8 m/s

$E = \frac{6.626 * 10^{-34}Js* 3*10^{8}m/s }{703.2*10^{-9} m}=2.83*10^{-19}J$