A wholesaler is offering two different package deals of roses and carnations to florists. One package contains 20 dozen roses and 34 dozen carnations for $504.00. The other package contains 15 dozen roses and 17 dozen carnations for $327.00. Let x = cost of one dozen roses Let y = cost of one dozen carnations a. Write a system of equations for this problem. Solve this system for the cost of one dozen roses and the cost of one dozen carnations.

Respuesta :

Answer:

Substitute into 20x+34y=504 ot solve for y:

20*15+34y = 504

300 + 34y = 504

34y = 204

y = 6

Step-by-step explanation:

A wholesaler is offering two different package deals of roses and carnations to florists. One package contains 20 dozen roses and 34 dozen carnations for $504.00. The other package contains 15 dozen roses and 17 dozen carnations for $327.00.  

Let x = cost of one dozen roses  

Let y = cost of one dozen carnations  

a. Write a system of equations for this problem.  

1st; 20x+34y= 504

2nd: 15x+17y=327  

b. Which equation can be multiplied by a coefficient to create an opposite coefficient? 2nd is the best choice

What is that value? -2  

c. Solve this system for the cost of one dozen roses and the cost of one dozen carnations.

1st: 20x+34y=504

3rd: -30x-34y=-654

 

--------

Add 1st and 3rd to get:

-10x = -150

x = 15 (# of dozens of roses)

-------------

Substitute into 20x+34y=504 ot solve for y:

20*15+34y = 504

300 + 34y = 504

34y = 204

y = 6 (# of dozens of carnations)

╦────────────────────────────╦

│Hope this helped  _____________________│    

│~Derelis ____________________________ │

╨___________________________________╨