Question

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a rigid cylinder of gas contains 450 grams of gas at pressure of 7.2 atmospheres. what will be the new pressure of the gas if the temp does not change but 100 grams of the gas leak out? ​

Answer 1

Answer:

Explanation:

The Ideal Gas Law states that PV=nRT.

Rearrange that into P/n=RT/V.

In this case, the cylinder is rigid so the volume, V, does not change.

Temperature does not change either.

Out of 450 grams of gas, 150 grams leak out. So only 450-150 = 300 grams is left.

n is number of moles which is dependent on mass:

n1/n2 = 450/300 = 3/2

P1/n1 = RT/V = P2/n2

P2 = P1/n1*n2

= 7.2/3*2

= 4.8 atmosphere

Answer 2

Answer:

Explanation:

100 grams of the gas leak out

no. of molecules before n after = 450/(450-100)

= 450/350

= 9/7

vol n temp are constant

so P (before)/P(after) = no. of molecules before n after = 9/7

P(after) = P(before) * 7/9

= 7.2*7/9

= 5.6atm