Step-by-step explanation:
The equations are
u - v = 1416%2F3.2 (1) (effective speed flying against the wind)
u + v = 1416%2F2.4 (2) (effective speed flying with the wind)
where "u" is the aircraft speed at no wind and "v" is the speed of wind.
Simplify (1) and (2):
u - v = 442.5 (3)
u + v = 590. (4)
Add equations (3) and (4). You will get
2u = 1032.5 ----> u = 1032.5%2F2 = 516.25.
Thus we found the speed of the aircraft at no wind. It is 516.25 mph.
Now from equation (4) v = 590 - 516.25 = 73.75 mph.
Answer. the speed of the aircraft at no wind is 516.25 mph. The speed of wind is 73.75 mph.
Solved.
It is a typical "tailwind and headwind" word problem.
