Respuesta :

Answer:   " 400 ."  

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                  →   " 96 " is 24% of:  "400 ."

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Step-by-step explanation:

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Note that:  " 24% "  =  " 24 / 100 "  =  " (24 ÷ 100)"  =  0.24 .

Note: when "dividing" a number by "100" ; one moves the decimal space back "2 (two) spaces."

→  "Dividing" by "100 " :

when doing so; "dividing" means moving the decimal space "backward" ;

   Thus, take the number;  "24" ;  which is:  " 24. " ;  and move it back

   "2 (two) spaces" ; since there are "2 (two) zeros" in "100";  

→  So;  "24." divided by "100" =  .24 ;  write as:  0.24 ;

→ Or; use a calculator:  "(24÷100) = 0.24 " .

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Back to the question:

"96 is 24% of what number? " ;

→  96 = (0.24) * n ;

in which:  "n" is the "number" for which we want to solve.

→ Divide each side of the equation by: "(0.24)" ;

 to isolate:  "n" on one side of the equation; & to solve for "n" ;

→ 96 = (0.24) n ;

↔  (0.24) n = 96 ;

Divide Each Side of the equation by:  "(0.24)" ; as follows:

→  (0.24) n / (0.24) = 96 / (0.24) ;

→  n = 96 / (0.24) ;

→  n = 400 .

The answer is:  " 400 " .

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Other method:

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 Note:  24% = 24/100 = (24÷4) / (100÷4) =  6/ 25 ;

→  Question:  "96 is 24% of what number?" ;

Rewrite as:  "96 is "6/25" of what number?" ;

→  "96 = (6/25) n " ;  Solve for "n" ; the number we wish to obtain;

↔  (6/25)n  = 96 ;

↔  (6n/25)  = 96 ;

→  6n = 96 * 25 ;

→  6n = 2400;

Divide each side of the equation by "6" ;

to isolate "n" on one side of the equation; and to solve for "n" :

→  6n/ 6 = 2400/6 ;

to get:

→  n = 400 .

The answer is:  "400" .

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Variant:

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When we have:  

→  6n = 96 * 25 ;  ← {as aforementioned} ;  

We can divide each side of the equation by "6" ;

to isolate "n" on one side of the equation;  

 →  since "96" on the "right-hand side" divided by "6" into a whole number integer;  that is:  "(96 ÷ 6 = 16) . " '

→  6n / 6 = [96 * 25] / 6  ;

to get:

→   n = 16 * 25 ;

Now, multiply to solve for "n" ;

→  n = 400 .

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The answer is: " 400 . "

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Hope this is helpful to you!

    Best wishes in your academic pursuits

            — and within the "Brainly" community!

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