So we should take x=0
1/2(0) - 1/3y = -3
0-1/3y= -3
y= -3 : -1/3
y= -1/3 *3/11 = 1
so the first is : x=0 , y=1
1/2 x - 0 = -3
1/2x=-3
x= -3 : 1/2
x=1/2 * 3/1 = 3/2 = 1,5
So here is x= 1,5 , y=0.
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The second equ
x-5y= 7
Let's take x as 0
0-5y = 7
-5y=7
y= 7/-5
y= -1,4
x= 0 . y= -1,4
Now let's take y=0
x- (5*0) =7
x-0=7
x=7
x=7 , y=0
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If we make it in the grid cordinates of solution of this equ are (3;-1)
ps : I HOPE I HADNT DO ANY MISTAKE :)