Respuesta :

Arvi
So we should take x=0 
1/2(0) - 1/3y = -3
0-1/3y= -3 
y= -3 : -1/3
y= -1/3 *3/11 = 1 

so the first is : x=0 , y=1   

1/2 x - 0 = -3 
1/2x=-3 
x= -3 : 1/2
x=1/2 * 3/1 = 3/2 = 1,5 

So here is  x= 1,5 , y=0. 

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The second equ 

x-5y= 7 
Let's take x as 0 
0-5y = 7 
-5y=7
y= 7/-5
y= -1,4 

x= 0 .  y= -1,4 

Now let's take y=0 
x- (5*0) =7
x-0=7
x=7 

x=7 , y=0 

__________________________

If we make it in the  grid cordinates of solution of this equ are (3;-1) 

ps : I HOPE I HADNT DO ANY MISTAKE :) 



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