Question

Find two consecutive even integers such that the smaller added to two times the larger gives a sum of 16

Answer 1

Answer:

Integer 1 = 4

Integer 2 = 6

 

Step-by-step explanation:

If you have two unknown consecutive even integers, you could call them as follows:

 

Integer 1 = x

Integer 2 = x+2

 

Your question claims that the smaller added to two times the larger gives a sum of 16.

 

So

 

Integer 1 + 2*(Integer 2) = 16

 

x + 2*(x+2) = 16

 

x + 2x + 4 = 16

 

3x = 12

 

x = 4

 

Since x is 4, this is your smaller integer. Your larger integer, therefore, would be x + 2, or 4 + 2 = 6.

 

Integer 1 = 4

Integer 2 = 6

 

Hope this helps.