Question

is there an ordered pair that is a solution to both 4x+3y<12 and -x+3y<-3

Answer 1

Answer:

See below.

Step-by-step explanation:

4x + 3y < 12

-x + 3y < -3

First find where the 2 lines intersect

4x + 3y = 12

-x + 3y = -3

Subtract :

5x = 15

x = 3

and y = -3 + 3 / 3 = 0

So they intersect at the point (3,0).

Therefore there are many  ordered pairs below these 2 lines that satisfy this inequality.