Question

Alessandro wrote the quadratic equation –6 = x2 + 4x – 1 in standard form. What is the value of c in his new equation?

Answer 1

Answer:

5

Step-by-step explanation:

To write it in standard form, we set the equation equal to 0.  To do this, we add 6 to each side:

-6+6 = x² + 4x - 1 + 6

0 = x² + 4x + 5

The related function is

y = x² + 4x + 5

The value of c in this function is 5.

Answer 2

The value of c in the new equation is 5 if the Alessandro wrote the quadratic equation –6 = x² + 4x – 1 in standard form.

What is a quadratic equation ?

Any equation of the form $\rm ax^2+bx+c=0$ where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.

As we know, the formula for the roots of the quadratic equation is given by:

$\rm x = \dfrac{-b \pm\sqrt{b^2-4ac}}{2a}$

We have:

Alessandro wrote the quadratic equation:

–6 = x² + 4x – 1

0  = x² + 4x – 1 + 6

0  = x² + 4x +5

x² + 4x +5 = 0

Standard form: $\rm ax^2+bx+c=0$

On comparing, we get:

c = 5

Thus, the value of c in the new equation is 5 if the Alessandro wrote the quadratic equation –6 = x² + 4x – 1 in standard form.

Learn more about quadratic equations here:

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