Geometry help! Find part B

Answer: It looks like Part B is about 4 times that of part A.
Step-by-step explanation: I think the answer would be 12.
A would be 3. B would be 12.
I'm terribly sorry if it is wrong.
Answer:
Step-by-step explanation:
Notice that side [tex]b[/tex] is a leg ot the triangle at the right side, the hypothenuse is [tex]z[/tex] and the other leg is [tex]y[/tex].
We know by given that [tex]a+b=15[/tex], where [tex]a+b[/tex] is the hypothenuse of the bigger right triangle, and [tex]z[/tex] and [tex]x[/tex] are the legs. Using trigonometric reasons, we have
[tex]cos(30\°)=\frac{z}{15}[/tex]
But, [tex]cos(30\°)=\frac{\sqrt{3} }{2}[/tex]
Then,
[tex]\frac{\sqrt{3} }{2} =\frac{z}{15}\\ z=\frac{15\sqrt{3} }{2}[/tex]
Then, in the triangle at the right side
[tex]cos(30\°)=\frac{b}{\frac{15\sqrt{3} }{2} } \\\frac{\sqrt{3} }{2} =\frac{b}{\frac{15\sqrt{3} }{2} } \\\frac{\sqrt{3} }{2}=\frac{2b}{15\sqrt{3} } \\15\sqrt{3} \sqrt{3} =4b\\4b=15\times 3\\b=\frac{45}{4}[/tex]
Therefore, the answer is 45/4.