Answer:
8y^2 - 10y + 3
Step-by-step explanation:
(2y – 1)(4y – 3)
Using FOIL
=(2y)(4y) -(2y)(3) - (1)(4y) - (1)(-3)
= 8y^2 - 6y - 4y + 3
= 8y^2 - 10y + 3
Answer:
8y² - 10y + 3
Step-by-step explanation:
In order to do this, you must use FOIL: First Outer Inner Last.
First, you must multiply the first terms in each parentheses:
2y(4y)=8y²
Next, you must multiply the two outer end numbers, which are 2y and -3:
2y(-3) = -6y
Then, you must multiply the two inner numbers, which are -1 and 4y:
-1(4y) = -4y
Finally, you must multiply the last numbers in each parentheses, which are -1 and -3:
(-1)(-3) = 3
Then, you add them all up:
8y²+(-6y)+(-4y)+3 = 8y² - 10y + 3