Explain why f(x)= 1/(x-x3)^3 is not continuous at x = 3.

Answer: Option b.
Step-by-step explanation:
1. You have the function [tex]f(x)=\frac{1}{(x-3)^{3}}[/tex] given in the problem above.
2. You must keep on mind that. by definition, the division by zero does not exist.
3. The value x=3 makes the denominator of the function f(x) equal to zero. Therefore you can conclude that the function shown in the problem is not defined at x=3.
The answer is the option b.
Answer:
Choice B is correct.
Step-by-step explanation:
We have given a function:
f(x)=1/(x-3)³
We have to explain that function is not continuous at x=3.
The domain is all possible values of x for which the function is defined.
When we put x=3 in the function, the denominator of function is zero.
f(x)=1/(x-3)³ = 1/(3-3)³ =1/0= undefined
Function is undefined when it contain 0 in its denominator.
That is why function is not continuous at x=3.
Choice B is correct.