Answer: Option a.
Step-by-step explanation:
Make the denominator equal to zero and solve for x, as following:
[tex]x^{2}+8x-9=0[/tex]
Choose two numbers whose sum is 8 and whose product is 9.
Then:
[tex](x-1)(x+9)=0\\x=1\\x=-9[/tex]
Therefore, based on this, you can conclude that the function is continuous at everty real number except x=1 and x=-9.
