Respuesta :
Asuume that the distribution in the small sample is representative of the whole. We can first compute the fraction of yellow in the sample:
[tex]Y=\frac{y}{total} = \frac{y}{r+y+b+p} = \frac{20}{15+20+12+8}=\frac{20}{55}=\frac{4}{11}[/tex]
We can tehen use this fractino to compute the expected number of yellow in a sample of 22 total beans:
[tex]Y_{22} = 22 \times \frac{4}{11} = 7.999999 [/tex]
There will be about 8 yellow beans.
[tex]Y=\frac{y}{total} = \frac{y}{r+y+b+p} = \frac{20}{15+20+12+8}=\frac{20}{55}=\frac{4}{11}[/tex]
We can tehen use this fractino to compute the expected number of yellow in a sample of 22 total beans:
[tex]Y_{22} = 22 \times \frac{4}{11} = 7.999999 [/tex]
There will be about 8 yellow beans.
Answer:
You can expect 8 yellow jelly beans.
Step-by-step explanation:
The ratio of yellow jelly beans to the total amount is:
20 : 55
If you want find the rate of 20 yellow jelly beans to the total amount, you would have to divide:
20 / 55 = 0.36363636 (long series of number continues)
Now that you have the rate of yellow jelly beans, you can use that rate to find the estimated amount of yellow jelly beans in a total of 22:
0.36363636 * 22 = 8
Hope this helped :))