Respuesta :

3 so that is the answer

The solution of the inequality [tex]12[/tex] < [tex]y(8-y)[/tex] is 2 < y < 6.

interval notation: [tex](2, 6)[/tex]

Given:

           [tex]12[/tex] < [tex]y(8-y)[/tex]

Rewrite in standard form

[tex]8y-y^{2} -12[/tex] > [tex]0[/tex]

Multiply both side by -1 (reverse the enequality)

[tex]y^{2}-8y+12[/tex] < [tex]0[/tex]

[tex]y^{2} - 6y-2y+12[/tex] < [tex]0[/tex]

[tex]y(y-6)-2(y-6)[/tex] < [tex]0[/tex]

[tex](y-6)(y-2)[/tex] < 0

Identify the interval

[tex]2[/tex] < [tex]y[/tex] < [tex]6[/tex]

Therefore, interval notation: (2, 6)

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