Respuesta :
The correct answers are
Exothermic:
H2 + Br2 → 2HBr, ΔH = -73 kJ
CH4 + 2O2 → CO2 + 2H2O, ΔH = -890 kJ
Endothermic
2NH3 → N2 + 3H2, ΔH = 92 kJ
2HCl → H2 + Cl2, ΔH = 184 kJ
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Answer:
H2 + Br2 → 2HBr, ΔH = -73 kJ ⇔ Exothermic
CH4 + 2O2 → CO2 + 2H2O, ΔH = -890 kJ ⇔ Exothermic
2NH3 → N2 + 3H2, ΔH = 92 kJ ⇔ Endothermic
2HCl → H2 + Cl2, ΔH = 184 kJ ⇔ Endothermic