A reaction was run with an initial concentration of 0.15 m. the half-life at 800 k was determined to be 1.751×10-4 s. the value of the half-life is independent of the initial concentration of the reactant present. what is the value of the rate constant at 800 k?

Respuesta :

Answer:

3.95 x 10³ s⁻¹.

Explanation:

∵ The value of the half-life is independent of the initial concentration of the reactant present.

∴ The reaction is a first order reaction.

  • The relation between half-life (t1/2) and rate constant for the first order reaction is: (t1/2) = ln2/k = 0.693/k.

∴ k = ln2 / (t1/2) = 0.693 / (1.751 x 10⁻⁴ s) = 3.95 x 10³ s⁻¹.

The value of the rate constant for the reaction at 800 K is 3.957×10³ s¯¹

What is half life?

This is the time taken for half the original amount of a substance to decay.

The half-life is related to the decay constant according to the following equation:

Decay constant (K) = 0.693 / half-life (t½)

K = 0.693 / t½

How to determine the decay constant

  • Half-life (t½) = 1.751×10¯⁴ s
  • Decay constant (K) =?

K = 0.693 / t½

K = 0.693 / 1.751×10¯⁴

K = 3.957×10³ s¯¹

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