Question

Which choice is equivalent to the product below when x^0?HELP HELP PLEASE PLEASE HELP PLEASE PLEASE HELP HELP PLEASE HELP PLEASE PLEASE HELP PROBLEM IN THE PHOTO BELOW

Answer 1

The part C is the correct one.

$\sqrt{ \frac{x}{3} } \times \sqrt{ \frac{2x}{6} } = \sqrt{ \frac{2 {x}^{2} }{18} } = \sqrt{ \frac{ {x}^{2} }{9} } = \frac{x}{3}$

Answer 2

Answer:

c x/3

Step-by-step explanation:

sqrt(2x/3) * sqrt(x/6)

We know that  sqrt(a) sqrt(b) = sqrt(ab)

sqrt(2x^2/18)

Simplifying inside the square root

sqrt(x^2/9)

We know sqrt(a/b) = sqrt(a)/sqrt(b)

sqrt(x^2)/sqrt(9)

x/3