Question

Ozone decomposes to oxygen according to the equation 2o3(g)⟶3o2(g).2o3(g)⟶3o2(g). write the equation that relates the rate expressions for this reaction in terms of the disappearance of o3 and the formation of oxygen.

Answer 1

Answer:

The rate of the reaction = (the rate of disappearance of O₃)/2 = (the rate of formation of O₂)/3.

Explanation:

• As the equation of ozone decomposition to oxygen is:

2O₃ → 3O₂.

The rate of the reaction = - d[O₃]/(2.dt) = d[O₂]/(3.dt).

where, - d[O₃]/(dt) is the rate of disappearance of O₃.

d[O₂]/(dt) is the rate of formation of O₂.

∴ The rate of the reaction = (the rate of disappearance of O₃)/2 = (the rate of formation of O₂)/3.

Answer 2

Rate expression shows the change in concentration of reactant and product over time.

The rate expression of the reaction in terms of the disappearance of $\bold{O_3 }$  $=\bold{\dfrac{the\; rate\; of\; disappearance\; of\; O_3}{2} }$

The formation of oxygen is $=\bold{\dfrac{the\; rate\; of\; disappearance\; of\; O_2}{3} }$

What is rate expression for the reaction?

The rate expression for the reaction is the change in the amount of reactant and product per unit time.

Given,

The equation

$\bold{2O_3(g)\rightarrow 3O_2(g) }$

The rate of reaction is

$\bold{ \dfrac{- d[O_3]}{(2.dt)} = \dfrac{d[O_2]}{(3.dt).} }$

$\bold{ \dfrac{- d[O_3]}{(2.dt)}\;}$ is the rate of disappearance of ozone

$\bold{ \dfrac{d[O_2]}{(3.dt).} }}$ is the rate of formation of oxygen.

Thus, The rate of disappearance of ozone is $=\bold{\dfrac{the\; rate\; of\; disappearance\; of\; O_3}{2} }$

The rate of formation of oxygen is $=\bold{\dfrac{the\; rate\; of\; disappearance\; of\; O_2}{3} }$

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