Answer:
[tex]\large\boxed{(f-g)(144)=0}[/tex]
Step-by-step explanation:
[tex]f(x)=\sqrt{x}+12\\g(x)=2\sqrt{x}\\\\(f-g)(x)=f(x)-g(x)\\\\\text{Substitute:}\\\\(f-g)(x)=\sqrt{x}+12-2\sqrt{x}=12-\sqrt{x}\\\\(f-g)(144)\to\text{put x = 144 to the equation}\\\\(f-g)(144)=12-\sqrt{144}=12-12=0[/tex]
