What are the zero of f(x)=x^2-10x+25
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Hello from MrBillDoesMath!
Answer:
x = 5 only
Discussion:
x^2 - 10x + 25.
Note that (-5)*(-5) = 25, the constant term in f(x), and -5 + -5 = -10, the coefficient of x in f(x). This suggests that the factorization of f(x) is
f(x) = (x-5)^2
Hence f has a single (repeated or double) root, x = 5, which is Choice D
Thank you,
MrB
Answer:
D. x = 5 only
Step-by-step explanation:
x^2 - 10x + 25 = 0
(x +/- ?) (x +/- ?) = 0
-5 X -5 = 25
-5 + -5 = -10
(x - 5) (x - 5)
x = 5, x = 5